Areas found by Integration

Look at the above area
bounded by the curve, x-axis, x = a, and x = b. The area described
is an irregular area which has no pat formula in geometry. To find
the area of the above enclosure, we can use integration. If you recall,
integration is a summation. We will sum an infinite number of rectangles
whose width approaches zero!! The integral then approaches the exact
area under the curve! The following is a basic interpretation of
the integral.
This implies to find
the area, you need to know the right-hand limit, left-hand limit and the
upper and lower limit. The curve for the above figure has the equation
f(x) = x2 .
Thus to find the area, the integral would be
The zero in the formula
represents the x-axis. y=0!!
Click for Rectangle Approximation Methold (Manipula Math)
Sample problems!!
1) Find the area
bounded by x-axis, f(x) = x2
- 3x and the lines x = 1 and x = 3.
a) Graph the region
above!!
The area to integrate
must be an enclosed area. This time the upper bound is the x-axis,
the lower bound is the curve and the right boundary is x = 3 and the left
boundary is x = 1. The picture looks like:
The integral and its solution
is below:
Therefore, the area is 10/3
square units!
2) Find the area
bound by the curves f(x) = 2x2
and g(x) = x + 1
Solution: Graph
it first!!
You need to calculate
where these curves intersect to find the left and right boundary.
The line is the upper boundary and the parabola is the lower boundary.
To find the intersection points, set the two equations equal and solve:
2x2
= x + 1
2x2
- x - 1 = 0
(2x + 1)(x - 1) = 0
x = 1 and x = -1/2
Thus, the right boundary
is x = 1 and the left boundary is x = -1/2!!
Here is the integral and
its solution:
3) Find the area
between the x-axis and the graph of f(x) = x2
-4 from
x = 0 to x = 3.
Solution: Graph the
equation and identify the area.
Notice that the area
this time is in two parts. The first area has the x-axis as the top
boundary and the curve as the lower boundary. The left limit is x
= o and the right limit is x = 2. The second area has the curve as
the top boundary and the x-axis as the lower boundary. The left limit
is x = 2 and the right limit is x = 3. You need two integrals to
solve the problem. The integrals and solution is:
Hope this was a help
for you!! The sample test is next!! Have a great summer and
be ready for an exciting year at college. I wish all of you good
luck and it was a pleasure being your instructor this year!! You
were a great bunch of students!! Stay that way!!


